1249. Minimum Remove to Make Valid Parentheses
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Given a string s of '(' , ')' and lowercase English characters.
Your task is to remove the minimum number of parentheses ( '(' or ')', in any positions ) so that the resulting parentheses string is valid and return any valid string.
Formally, a parentheses string is valid if and only if:
- It is the empty string, contains only lowercase characters, or
- It can be written as
AB(Aconcatenated withB), whereAandBare valid strings, or - It can be written as
(A), whereAis a valid string.
Example 1:
Input: s = "lee(t(c)o)de)" Output: "lee(t(c)o)de" Explanation: "lee(t(co)de)" , "lee(t(c)ode)" would also be accepted.
Example 2:
Input: s = "a)b(c)d" Output: "ab(c)d"
Example 3:
Input: s = "))(("
Output: ""
Explanation: An empty string is also valid.
Constraints:
1 <= s.length <= 105s[i]is either'(',')', or lowercase English letter.
Hints
Hint 1
Each prefix of a balanced parentheses has a number of open parentheses greater or equal than closed parentheses, similar idea with each suffix.
Hint 2
Check the array from left to right, remove characters that do not meet the property mentioned above, same idea in backward way.